如何使用div指令在x86汇编中找到余数? [英] How to use the div instruction to find remainder in x86 assembly?

问题描述

mov eax, 0
mov ebx, 0
mov edx, 0
mov ax, 31
mul cx
mov bx, 12
div bx
add bp, ax
mov eax, 0
mov ebx, 0
mov bp, bp
mov al, 7
div al

有人能告诉我这段代码中的div指令有什么问题吗，所以当我调试我计算出的每一个bp数时，当我除以al时，它给我1作为余数，为什么会这样?

can anyone tell me whats wrong with the div al instruction in this block of code, so as I'm debugging every number of bp i calculated, when i divide by al it give me 1 as the remainder, why is this happen?

其余部分应存储回ah寄存器

the remainder should be store back to ah register

预先感谢

修改后的代码:

mov eax, 0
mov ebx, 0
mov edx, 0
mov ax, 31
mul cx
mov bx, 12
div bx
add bp, ax
mov eax, 0
mov ebx, 0
mov ax, bp
mov bl, 7
div bl
mov al, 0

推荐答案

修改后的代码:

mov eax, 0
mov ebx, 0
mov ax, 31
mul cx
mov bx, 12
div bx
add bp, ax
mov eax, 0
mov ebx, 0
mov edx, 0
mov ax, bp
mov bx, 7
div bx
mov esi, edx 
mov eax, 0

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