比较堆栈中的两个值? [英] Compare two values from the stack?

问题描述

我卡住了 在我要比较两个值的汇编代码中 堆栈.

I stuck in my assembler code where I want to compare two values of the stack.

x86，语法AT& T

x86, Syntax AT&T

cmpl -4(%ebp), 4(%ebp)

错误:'cmp'的内存引用过多

Error: too many memory references for `cmp'

我认为不可能基于乘数和ebp比较两个值.有什么建议吗?

I think it is not possible to compare two values based on a multiplier and ebp. Any suggestions ?

推荐答案

您可以使用CMPSD指令比较内存中的两个值.

You can compare two values in memory using the CMPSD instruction.

Op想做的事情等同于:

Op wants to do something equivalent to:

  cmpl -4(%ebp), 4(%ebp)

他可以通过将感兴趣的内存位置的地址分别放在ESI和EDI中，然后使用

He can do that by placing the addresses of the memory locations of interest in ESI and EDI respectively, and then using the CMPSD memory-to-memory string-compare instruction:

  lea   -4(%ebp), %esi
  lea    4(%ebp), %edi
  cmpsd

(原谅我对AT& T语法的非专业滥用).

(forgive my non-expert abuse of AT&T syntax).

与实践中的任何人都不同.此处提供的其他答案(将值加载到寄存器中并进行比较)更加实用.如果没有其他问题，那么这些解决方案只会烧掉一个寄存器，而这个hack会烧掉两个寄存器.

That's different than anybody would do this in practice. The other answers provided here (load a value into a register and compare) are much more practical. If nothing else, those solutions only burn one register, and this hack burns two.

课程:在汇编程序中，几乎总有不止一种为猫皮剥皮的方法.

Lesson: in assembler, there's almost always more than one way to skin a cat.

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