如何将十六进制代码转换为x86指令 [英] How to turn hex code into x86 instructions

问题描述

我正在尝试制作一个脚本或程序，该脚本或程序将使用给定的字节(以十六进制形式)，并将其转换为x86指令(例如c3-> retq)

I'm trying to make a script or program that will take given bytes (given in hexadecimal), and convert them into a x86 instructions (For example c3 -> retq)

我尝试通过在仅包含程序集的文件上调用gcc -c来做到这一点

I've tried doing it by calling gcc -c on an assembly file just containing

retq
retq

，然后使用脚本在"c3 c3"所在的位置插入字节，然后使用objdump -d查看现在的内容.但是，除非我仅传递与原始指令字节相同大小的指令，否则它似乎会弄乱文件的格式.

and then using a script to insert bytes where it says "c3 c3", then using objdump -d to see what it says now. But it seems that it messes up the format of the file unless I only pass an instruction of the same size as the original instruction bytes.

我正在使用SSH，BASH终端在Raspbian Pi(基于Linux的操作系统)上运行它.我正在使用BASH Shell脚本和python，以及此处列出的工具和gdb.

I'm running it on a Raspbian Pi (A linux based operating system) using SSH, BASH terminal. I'm using BASH shell scripts and python, as well as the tools listed here, and gdb.

推荐答案

反汇编平面二进制文件:objdump -D -b binary -m i386 foo.bin.或者使用汇编源中的.byte指令创建目标文件，例如将.byte 0xc3放入foo.s然后gcc -c foo.s然后objdump -d foo.o

Disassemble flat binary file: objdump -D -b binary -m i386 foo.bin. Or create an object file using .byte directives from assembly source, e.g. put .byte 0xc3 into foo.s then gcc -c foo.s then objdump -d foo.o

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