CMAKE_BUILD_TYPE =发布是否暗含-DNDEBUG? [英] Does CMAKE_BUILD_TYPE=Release imply -DNDEBUG?

问题描述

CMAKE_BUILD_TYPE=Release 隐式暗示 如果不是::期望发生这种暗示是否合理?

If not: isn't it reasonable to expect that this implication takes place?

我想知道在我的 CMakeLists.txt 中遵循 CMake 代码是否多余:

I want to know if following CMake code is redundant in my CMakeLists.txt:

if (NOT CMAKE_BUILD_TYPE MATCHES Debug)
    add_definitions(-DNDEBUG)
endif()

推荐答案

是的，它是由CMake设置的.通过查看CMake代码可以发现，对于许多编译器来说，它是已设置的.可能他们只为接受此标志的这些编译器设置了它.这里是有关GCC的一行:

Yes, it is set by CMake. Grepping through the CMake code reveals, that for a host of compilers it is set. Probably they set it only for these compilers, which accepts this flag. Here one of the lines concerning GCC:

Modules/Compiler/GNU.cmake:  set(CMAKE_${lang}_FLAGS_RELEASE_INIT "-O3 -DNDEBUG")

但是请注意，许多项目会在不保留初始设置的情况下覆盖发行/调试标志，并且还会覆盖用户的定义.

But be aware that many projects overwrite release/debug flags without preserving the initial setting and also overwriting user's definitions.

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