如何断言函数调用不会在unittest中返回错误? [英] How to assert that a function call does not return an error with unittest?

问题描述

无论如何，unittest都可以断言一个函数调用不会导致错误，无论它是TypeError还是IOError等等.

Is there anyway with unittest to just assert that a function call does not result in an error, whether it is a TypeError, IOError, etc.

示例:

assert function(a,b) is not error

或

if not assertRaises function(a, b)

做到这一点的最佳方法是什么(不使用类)?我遇到的麻烦是，我在unittest中遇到的所有有用文档都是基于类的，而我不想使用基于类的

What is the best way to do this (without using classes)? The trouble I'm having is all the useful documentation I come a cross in unittest is all class based and I don't want to use class based.

完整示例:

def test_validate_params():
    assert test.validate_params('hackenv-re', 'test.username') is not errors
    assert test.validate_params('fakeenv', 'test.username') is error
    assert test.validate_params('hackevn-re', 'vagrant') is error
    counter += 1
    print "Test Passed {0}/5: validate_params".format(counter)

推荐答案

如果您的函数引发异常，则测试将失败.无需进行任何其他检查.如果您绝对愿意，可以执行以下操作:

If your function raises an exception, the test will fail. There is no need to do any additional checks. If you absolutely want to, you can do something like this:

try:
    function_under_test()
except Exception as e:
    self.fail("Unexpected exception %s" % e) 

(假设标准的Python单元测试)

(assuming standard Python unittest)

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