如何捕获特定的名称分配? [英] How to catch a particular name assignment?

问题描述

(基于此问题):

在设置对象的attribute时，可以覆盖对象的__setattr__魔术方法以具有其他指令.如:

One can override the __setattr__ magic method for an object to have additional instructions when an attribute of an object is set. As in:

class MyClass(object):
    def __init__(self, attribute=None):
        object.__init__(self)
        self.attribute = attribute


    def __setattr__(self, name, value):
        self.__dict__[name] = value
        if name == 'attribute':
            print("attribute's value is modified to {}.".format(
                                                        self.attribute))


if __name__ == '__main__':
    my_obj = MyClass(True)
    while True:
        my_obj.attribute = input()

• 如何在当前脚本中捕获特定的名称分配 无需使用类(特别是调用具有更多内容的方法 说明)?
• How can I catch a particular name assignment in the current script without using classes(specifically to call a method with more instructions)?

 

def b_is_modified():
    print("b is modified!")


if __name__ == '__main__':
    a = 3
    b = 4
    b = 5

为b分配值时如何调用b_is_modified?

推荐答案

基于此答案:

不能 被捕获(至少在python级别).

It can't be catched(at least in python level).

简单名称分配(b = 4)是语言本身的基础操作.它不是根据可以覆盖的较低级别的操作来实现的.只是是.

Simple name assignment(b = 4), as oppposed to object attribute assignment (object.b = 5), is a fundamental operation of the language itself. It's not implemented in terms of a lower-level operation that one can override. Assignment just is.

这篇关于如何捕获特定的名称分配?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！