将Func委托与Async方法一起使用 [英] Using Func delegate with Async method
本文介绍了将Func委托与Async方法一起使用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试将Func与异步方法一起使用.而且我遇到了错误.
I am trying to use Func with Async Method. And I am getting an error.
无法将异步lambda表达式转换为委托类型
'Func<HttpResponseMesage>'
.异步lambda表达式可能返回void,Task或Task<T>
,而这些都不可转换为'Func<HttpResponseMesage>'
.
Cannot convert async lambda expression to delegate type
'Func<HttpResponseMesage>'
. An async lambda expression may return void, Task orTask<T>
, none of which are convertible to'Func<HttpResponseMesage>'
.
下面是我的代码:
public async Task<HttpResponseMessage> CallAsyncMethod()
{
Console.WriteLine("Calling Youtube");
HttpClient client = new HttpClient();
var response = await client.GetAsync("https://www.youtube.com/watch?v=_OBlgSz8sSM");
Console.WriteLine("Got Response from youtube");
return response;
}
static void Main(string[] args)
{
Program p = new Program();
Task<HttpResponseMessage> myTask = p.CallAsyncMethod();
Func<HttpResponseMessage> myFun =async () => await myTask;
Console.ReadLine();
}
推荐答案
如错误所示,异步方法返回Task
,Task<T>
或void
.因此,要使其正常工作,您可以:
As the error says, async methods return Task
,Task<T>
or void
. So to get this to work you can:
Func<Task<HttpResponseMessage>> myFun = async () => await myTask;
这篇关于将Func委托与Async方法一起使用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文