Python SQLAlchemy:AttributeError:“列"对象和“比较器"对象都没有属性“模式" [英] Python SQLAlchemy: AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema'
问题描述
我尝试在项目中创建一个新的数据库,但是在运行脚本时遇到此错误,我有另一个使用类似定义的项目,该项目以前可以使用,但现在却出现相同的错误. 我正在使用Python 2.7.8,SQLAlchemy模块的版本是0.9.8. 顺便说一句,一个项目使用Flask-SQLAlchemy,它运行良好. 我很迷惑. 追溯信息如下:
I tried creating a new database in my project, but I got this error when I run the script, I have another project using similar definition, it worked before, but now it get the same error now. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, a project used Flask-SQLAlchemy, it works well. I am confused. The traceback information is following:
Traceback (most recent call last):
File "D:/Projects/OO-IM/db_create.py", line 4, in <module>
from models import Base
File "D:\Projects\OO-IM\models.py", line 15, in <module>
Column('followed_id', Integer(), ForeignKey('user.id'))
File "C:\Python27\lib\site-packages\sqlalchemy\sql\schema.py", line 369, in __new__
schema = metadata.schema
File "C:\Python27\lib\site-packages\sqlalchemy\sql\elements.py", line 662, in __getattr__
key)
AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema'
from sqlalchemy import create_engine, Column, String, Integer, Text, DateTime, Boolean, ForeignKey, Table
from sqlalchemy.orm import sessionmaker, relationship, backref
from sqlalchemy.ext.declarative import declarative_base
SQLALCHEMY_DATABASE_URI = "mysql://root:mysqladmin@localhost:3306/oo_im?charset=utf8"
Base = declarative_base()
# TODO:AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema'
friendships = Table('friendships',
Column('follower_id', Integer(), ForeignKey('user.id')),
Column('followed_id', Integer(), ForeignKey('user.id'))
)
class User(Base):
__tablename__ = 'user'
id = Column(Integer(), primary_key=True)
account = Column(String(32), unique=True, nullable=False)
password = Column(String(32), nullable=False)
followed = relationship("User",
secondary=friendships,
primaryjoin=(friendships.c.follower_id == id),
secondaryjoin=(friendships.c.followed_id == id),
backref=backref("followers", lazy="dynamic"),
lazy="dynamic")
def __init__(self, account, password, followed=None):
self.account = account
self.password = password
if followed:
for user in followed:
self.follow(user)
def follow(self, user):
if not self.is_following(user):
self.followed.append(user)
return self
def unfollow(self, user):
if self.is_following(user):
self.followed.remove(user)
return self
def is_following(self, user):
return self.followed.filter(friendships.c.followed_id == user.id).count() > 0
class ChatLog(Base):
__tablename__ = 'chatlog'
id = Column(Integer(), primary_key=True)
sender_id = Column(Integer(), ForeignKey('user.id'), nullable=False)
receiver_id = Column(Integer(), ForeignKey('user.id'), nullable=False)
send_time = Column(DateTime(), nullable=False)
received = Column(Boolean(), default=False)
content = Column(Text(), nullable=False)
engine = create_engine(SQLALCHEMY_DATABASE_URI, convert_unicode=True)
DBSession = sessionmaker(bind=engine)
推荐答案
表定义应为:
friendships = Table('friendships',
Base.metadata,
Column('follower_id', Integer(), ForeignKey('user.id')),
Column('followed_id', Integer(), ForeignKey('user.id'))
)
使用声明性语法定义表时,元数据通过Base的类声明继承,即
When defining tables using the declarative syntax, the metadata is inherited through the class declaration from Base, i.e.
Base = declarative_base()
class ChatLog(Base)
但是,当使用旧的Table语法定义表时,必须显式指定元数据.
but, when defining tables using the old Table syntax, the metadata must be explicitly specified.
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