如何以编程方式将2个或更多.WAV文件连接在一起? [英] How to join 2 or more .WAV files together programmatically?

问题描述

我需要能够将2个或多个.wav文件合并到一个.wav文件中.我必须使用C#以编程方式进行此操作(不能选择第三方产品).我知道System.Media.SoundPlayer类，但我不想播放.wav，而只是创建它.

I need the ability to join 2 or more .wav files together in to one .wav file. I must do this programmatically, using C# (3rd-party products are not an option). I know of the System.Media.SoundPlayer class, but I am not looking to play the the .wav, but only to create it.

推荐答案

这是使用 NAudio .这将确保仅连接数据块(与此CodeProject文章中的代码示例不同) 链接到另一个答案中).它还可以保护您，防止串联不共享相同格式的WAV文件.

Here's a basic WAV concatenation function built using NAudio. This will ensure that only the data chunks are concatenated (unlike the code example in this CodeProject article linked in another answer). It will also protect you against concatenating WAV files that do not share the same format.

public static void Concatenate(string outputFile, IEnumerable<string> sourceFiles)
{
    byte[] buffer = new byte[1024];
    WaveFileWriter waveFileWriter = null;

    try
    {
        foreach (string sourceFile in sourceFiles)
        {
            using (WaveFileReader reader = new WaveFileReader(sourceFile))
            {
                if (waveFileWriter == null)
                {
                    // first time in create new Writer
                    waveFileWriter = new WaveFileWriter(outputFile, reader.WaveFormat);
                }
                else
                {
                    if (!reader.WaveFormat.Equals(waveFileWriter.WaveFormat))
                    {
                        throw new InvalidOperationException("Can't concatenate WAV Files that don't share the same format");
                    }
                }

                int read;
                while ((read = reader.Read(buffer, 0, buffer.Length)) > 0)
                {
                    waveFileWriter.WriteData(buffer, 0, read);
                }
            }
        }
    }
    finally
    {
        if (waveFileWriter != null)
        {
            waveFileWriter.Dispose();
        }
    }

}

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