如何使用Javascript播放特定频率? [英] How to play a specific frequency with Javascript?
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问题描述
我想要一个像这样的函数:
I want a function that works like this:
playSound(345, 1000)
将以345 hz的音调播放1000毫秒.在JavaScript中最简单的方法是什么?我不介意它是使用样本(也许是罪孽之波,还是钢琴),还是使用计算机的硬件来生成声音.
Which would play a tone of 345 hz for 1000 milliseconds. What is the simplest way to achieve this in JavaScript? I don't mind if it uses a sample (maybe of a sin wave, or piano), or uses the computer's hardware to generate the sound.
推荐答案
As already pointed out in the comments, the way to do it is through the OscillatorNode
.
// create web audio api context
var audioCtx = new(window.AudioContext || window.webkitAudioContext)();
function playNote(frequency, duration) {
// create Oscillator node
var oscillator = audioCtx.createOscillator();
oscillator.type = 'square';
oscillator.frequency.value = frequency; // value in hertz
oscillator.connect(audioCtx.destination);
oscillator.start();
setTimeout(
function() {
oscillator.stop();
playMelody();
}, duration);
}
function playMelody() {
if (notes.length > 0) {
note = notes.pop();
playNote(note[0], 1000 * 256 / (note[1] * tempo));
}
}
notes = [
[659, 4],
[659, 4],
[659, 4],
[523, 8],
[0, 16],
[783, 16],
[659, 4],
[523, 8],
[0, 16],
[783, 16],
[659, 4],
[0, 4],
[987, 4],
[987, 4],
[987, 4],
[1046, 8],
[0, 16],
[783, 16],
[622, 4],
[523, 8],
[0, 16],
[783, 16],
[659, 4]
];
notes.reverse();
tempo = 100;
playMelody();
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