将值传递给路线 [英] Pass values to route

问题描述

我有一个物品清单.当用户单击某个项目时，该用户将被带到项目详细信息"页面.

I have a list of items. When the user clicks on an item, the user will be taken to item details page.

我想将包含商品详细信息(例如商品的图片网址)的对象传递给路线.但是，我不想在路由URL中公开它.

I want to pass an object containing item details(like item's image URL) to the route. However, I don't want to expose it in the routes url.

如果有办法像<a route-href="route: details; settings.bind({url: item.url})">${item.name}</a>那样做，那就是金.

If there were a way to do something like <a route-href="route: details; settings.bind({url: item.url})">${item.name}</a> that would be gold.

我已经看到，如果在路由配置中定义了属性，则可以将其传递给路由.但是，我不知道如何从模板更改它.另一种方法是定义一个单例并在其中存储值，然后将对象注入到目标路由.

I have seen properties can be passed to a route if defined in the route configuration. However, I don't know how to change that from the template. Another way could be is to define a singleton and store the values there and inject the object to the destination route.

有没有一种方法可以将值传递给视图中的路由(例如角度ui路由器param对象)?

Is there a way to pass values to routes from view (like angular ui-routers param object)?

推荐答案

好，所以我想出了一种方法，可以实现一些与我想要的目标更接近的目标:

Okay so I figured out a way to achieve something closer to what I wanted:

目标:将数据传递给路由，而不将其暴露在位置栏中.

Objective: Pass data to route without exposing them in the location bar.

比方说，我们有一个用户列表，我们希望将username传递到用户的个人资料页面，而无需将其定义为查询参数.

Let's say, we have a list of users and we want to pass the username to the user's profile page without defining it as a query parameter.

在视图模型中，首先注入Router，然后将数据添加到目标路由器:

In the view-model, first inject Router and then add data to the destination router:

goToUser(username) {
    let userprofile = this.router.routes.find(x => x.name === 'userprofile');
    userprofile.name = username;
    this.router.navigateToRoute('userprofile');
}

现在，当路线更改为userprofile时，您可以作为activate方法的第二个参数访问路线设置:

Now when the route changes to userprofile, you can access the route settings as the second parameter of activate method:

activate(params, routeData) {
    console.log(routeData.name); //user name
}

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