Automapper可以忽略void方法吗? [英] Can Automapper ignore void methods?

问题描述

我是Automapper的新手，所以不确定是否可行.

I am new to Automapper, so I am not sure if this is possible.

我想映射一个类，但可以忽略一个无效的方法.下面是我具有的代码的说明.运行此命令时，会收到以下异常消息.

I would like to map a class, but get it to ignore methods that are void. Below is an illustration of the code I have. When I run this I get the following exception message.

类型为'AutoMapper.AutoMapperMappingException'的未处理的异常 发生在AutoMapper.dll

An unhandled exception of type 'AutoMapper.AutoMapperMappingException' occurred in AutoMapper.dll

不幸的是，这不是更改接口的选项，所以我认为是否有可能缺少某种配置?

Unfortunately it isn't an option to change the interface, so I assume if this is possible there is some sort of configuration I am missing?

public interface IThing
{
    string Name { get; set; }
    void IgnoreMe();
}

public class Foo : IThing
{
    public string Name { get; set; }

    public void IgnoreMe()
    {
    }
}

class Program
{
    static void Main(string[] args)
    {
        var fooSource = new Foo {Name = "Bobby"};
        Mapper.CreateMap<IThing, IThing>();

        var fooDestination = Mapper.Map<IThing>(fooSource);
        Console.WriteLine(fooDestination.Name);
        Console.ReadLine();
    }
}

推荐答案

如果您使用的是

If you are using an interface as a destination type AutoMapper will dynamically create an implementation (proxy) type for you.

但是代理代仅支持属性，因此它为您的IgnoreMe方法抛出了不太描述性的异常.因此，您不能忽略您的IgnoreMe方法.

However the proxy generation only supports properties, so it throws this not too descriptive exception for your IgnoreMe method. So you cannot ignore your IgnoreMe method.

作为一种解决方法，您可以使用ConstructUsing重载之一明确指定应如何构造目标对象，在这种情况下，AutoMapper不会生成代理.

As a workaround you can explicitly specify how the destination objects should be constructed with using one of the ConstructUsing overloads in this case AutoMapper does not generate proxies.

Mapper.CreateMap<IThing, IThing>()
      .ConstructUsing((ResolutionContext c) => new Foo());

或者，除非没有充分的理由，否则您可以直接映射到Foo

Or unless you have no good reason, you can directly map to Foo

Mapper.CreateMap<IThing, Foo>();

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