如何从给定值获取平均值 [英] How to get average from given values

问题描述

我如何平均?我想找到GPA的平均值，学生总数和GPA的总数. 例如:

How do I average?. I am suppose to find the average of the GPA, total of students, and the total of GPA. example:

输入: 4 4 4 4

input: 4 4 4 4

输出: 学生总数:4

总GPA :16

平均GPA: 4

import java.util.Scanner;

public class practice {
    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        int count = 0;
        double GPA = 0, total = 0, average;

        System.out.println("Enter GPA");

        while (GPA >= 0) {
            GPA = keyboard.nextDouble();
            total = total + GPA;
            count++;
        }

        average = total / count;

        System.out.println("Total students: " + count);
        System.out.println("Total GPA " + total);
        System.out.println("Average GPA " + average);
    }
}

推荐答案

如果问题是您得到了错误的答案，则原因是此循环:

If the problem is that you're getting the wrong answer, the reason is this loop:

while (GPA >=0)
{
    GPA = keyboard.nextDouble();
    total = total + GPA;
    count++;
}

大概您打算在用户输入负数时退出循环.这样做有问题，它将在总数和计数中包含负数.您可以这样重写循环:

Presumably you intend the loop to exit when the user enters a negative number. What's wrong with it is that it will include the negative number in the total and count. You can rewrite the loop like this:

GPA = keyboard.nextDouble();
while (GPA >=0)
{
    total = total + GPA;
    count++;
    GPA = keyboard.nextDouble();
}

(其他解决方案也是可能的).在代码的后面，您将需要防止第一个数字为负.如果发生这种情况，count将为0，并且您要避免除以0并打印无意义的结果.

(Other solutions are possible). Later in your code, you will need to guard against the first number being negative. If that happens, count will be 0 and you want to avoid dividing by 0 and printing nonsense results.

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