使用Bash Shell提取JSON对象? [英] Extract JSON object using Bash shell?

问题描述

我有一个以下json文件，我正在寻找一种使用bash shell使用对象路径提取对象的方法.

I have a following json file and I'm looking for a way to extract object using object path using bash shell.

例如，如果我说extract('production-ap/ap-northeast-1')，那么它将返回我"accessKey": "OO"，"accountID": "99".

For example, if I say extract('production-ap/ap-northeast-1'), then it will return me "accessKey": "OO", "accountID": "99".

我喜欢bash shell脚本，但是对它的了解有限，请帮忙！

I like bash shell scripting but have limited knowledge of it, please help!

谢谢

{
    "production-ap": {
        "ap-northeast-1": {
            "accessKey": "OO",
            "accountID": "99"
        },
        "ap-northeast-2": {
            "accessKey": "AB",
            "accountID": "12"
        }
    },
    "production-eu": {
        "eu-west-1": {
            "accessKey": "CD",
            "accountID": "34"
        },
        "us-east-1": {
            "accessKey": "CD",
            "accountID": "34"
        }
    },
    "production-us": {
        "us-east-1": {
            "accessKey": "EF",
            "accountID": "56"
        },
        "us-east-2": {
            "accessKey": "EF",
            "accountID": "56"
        }
    },
    "stage-ap": {
        "ap-northeast-1": {
            "accessKey": "AK",
            "accountID": "78"
        },
        "ap-northeast-2": {
            "accessKey": "AK",
            "accountID": "78"
        }
    },
    "stage-eu": {
        "eu-west-1": {
            "accessKey": "AK",
            "accountID": "55"
        },
        "eu-west-2": {
            "accessKey": "AK",
            "accountID": "55"
        }
    },
    "stage-us": {
        "us-east-1": {
            "accessKey": "AK",
            "accountID": "30"
        },
        "us-east-2": {
            "accessKey": "AK",
            "accountID": "30"
        }
    },
    "private": {
        "us-west-2": {
            "accessKey": "z2",
            "accountID": "52"
        },
        "us-west-1": {
            "accessKey": "z2",
            "accountID": "52"
        }
    }
}

推荐答案

使用bash执行此操作会很困难.似乎有确实是 json解析器，写为shell脚本，尽管我不确定它们的坚固程度.我建议使用 jq 之类的东西，它可以作为单独的程序运行并可以在管道中使用.它是一个独立的可执行文件，用C编写.没有理由不将它与程序一起提供.

It's going to be flaky doing this using bash. There do seem to be json parsers written as shell scripts although I'm not sure how solid they are. I'd recommend something like jq which can run as a separate program and be used in a pipe. It's a standalone executable and written in C. There's no reason it can't be shipped along with your program.

这篇关于使用Bash Shell提取JSON对象?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！