从文件生成频率表 [英] generating frequency table from file

问题描述

给定一个输入文件，每行包含一个数字，我如何计算该文件中有多少次出现?

Given an input file containing one single number per line, how could I get a count of how many times an item occurred in that file?

cat input.txt
1
2
1
3
1
0

所需的输出(=> [1,3,1,1]):

desired output (=>[1,3,1,1]):

cat output.txt
0 1
1 3
2 1
3 1

如果该解决方案也可以扩展为浮点数，那就太好了.

It would be great, if the solution could also be extended for floating numbers.

推荐答案

您的意思是您要计算一个项目在输入文件中出现多少次?首先对它进行排序(如果输入始终像示例中那样是数字，则使用-n)，然后计算唯一结果.

You mean you want a count of how many times an item appears in the input file? First sort it (using -n if the input is always numbers as in your example) then count the unique results.

sort -n input.txt | uniq -c

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