awk-打开文件过多/日期解析 [英] awk - too many open files issue / date parsing

问题描述

我正在尝试分析以格式化日期列开头的日志文件: 06/22/2015 00:17:59

I'm trying to parse a log file that starts with a formatted date column: 06/22/2015 00:17:59

我正在使用以下代码将其转换为unix时间戳:

I'm using the following code to convert it into a unix timestamp:

unix="date -d\""$1" "$2"\" \"+%s\""; unix | getline timestamp;

但是，当我这样做时，awk失败并显示以下错误:

However, when I do this, awk fails with following error:

awk: (FILENAME=/dev/fd/63 FNR=263350) fatal: cannot open pipe 'date -d"06/22/2015 00:17:59" "+%s"' (Too many open files)

有什么方法可以处理此问题，或者以其他方式解析日期?

Any way to deal with this, or to parse the date differently?

推荐答案

您的问题是您需要关闭命令:

Your problem is that you need to close your command:

unix="date -d\""$1" "$2"\" \"+%s\""; unix | getline timestamp; close(unix)

如果不这样做，则会为输入文件中的每个记录打开一个新管道，这会导致您遇到问题.

If you don't do this, a new pipe is opened for each record in your input file, which leads to the problem that you are experiencing.

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