提取第n个字母(数字) [英] Extract every nth letter (number)

问题描述

我有一个带有以下行的文件:名称，空格和零和一的字符串，我需要提取零和一的字符串的每5n个字符，对结果求和，如果和不为0-将名称保存到另一个文件中.

I have a file with line: name, space and string of zero and one, and I need to extract every 5nth character of the string of zero and one, make a sum of the results and if the sum is not 0 - save the name into the other file.

1rt2 0001000000100000000000001010000100000000010000001000000100010010000000000000
1gh4 0001000000100000000000001010000100000000010000001000000100000010000000000000
3fg5 1000000100010010000000000000100000010000000001000000100000010000000000000000
45gh 1000000100000010000000000000100000010000000001000000000100010000000000000000

问题:如何提取比特串的第5个数字(字母)?解决方案越简单-越好...

The question: how to extract every 5th number (letter) of the bitstring? The more simplistic the solution - the better...

非常感谢！

推荐答案

sed -e '/ \(.........\)*........1/s/^\([^ ]*\) .*$/\1/;t;d'

将位置为1的行与9的倍数匹配(对于这些行，总和将不为0)，并打印该行的文件名部分.其他所有行均未打印.

Match the lines that have a 1 on a position that is a multiple of 9 (for these lines the sum will not be 0) and print the filename portion of that line. All other lines are not printed.

sed -e '/ \(.....\)*....1/s/^\([^ ]*\) .*$/\1/;t;d'

每5个0或1执行一次该操作.

will do the job for every 5th 0 or 1.

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