使用Awk搜索包含空格的字符串 [英] Using Awk to search for a string that has spaces

问题描述

我无法使用awk在文件中搜索字符串的最后一次出现.我正在将字符串传递给脚本示例主机名Ping失败".我不断收到awk:^未终止的字符串. #！/bin/sh

I'm having trouble searching for the last occurrence of a string in a file using awk. I'm passing a string to the script example "Ping has failed on hostname". I keep getting awk: ^ unterminated string. #!/bin/sh

LOG=/opt/netcool/omnibus/log/mttrapd.log
TMP_FILE=sitescope.$$
args="$*"

#ruby sitescope.rb

echo "looking for $1 "

tail -1000  $LOG > $TMP_FILE

echo "WORD = $args"

awk  '"/'$args'/" {f=$0} END{print f}' $TMP_FILE > data.out

rm -f $TMP_FILE

推荐答案

awk字符串周围的单引号的要点是将所有内容保留在第一个参数中(并防止shell替换).将参数作为

The point of the single-quotes around the awk string is to keep everything in the first argument (and prevent shell substitution). You can be a bit more flexable with how you put that argument together as

awk  "/$args/"' {f=$0} END{print f}' $TMP_FILE > data.out

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