打印与awk脚本匹配的文件名 [英] Printing name of files that match awk script

问题描述

根据我之前的问题

我有多个文本文件，可能有也可能没有用虚线包围的重复文本组.所有lorem ipsum文本都不应包含在输出中.

I have multiple text files that may or may not have repeating groups of text surrounded by dashed lines. All the lorem ipsum text should not be included in the output.

$ cat /tmp/testAwk/file1.txt


--------------
important text one
important text two
--------------

Lorem ipsum dolor sit amet
consectetur adipiscing elit

--------------
important text three
important text four
--------------

sed do eiusmod tempor incididunt
ut labore et dolore magna aliqua

Ut enim ad minim veniam
quis nostrud exercitation ullamco laboris nisi ut aliquip
ex ea commodo consequat


$ cat /tmp/testAwk/file2.txt
Duis aute irure dolor in reprehenderit

--------------
important text one
important text two
--------------

in voluptate velit esse cillum dolore
eu fugiat nulla pariatur

non proident, sunt

--------------
important text three
important text four
--------------

Excepteur sint occaecat cupidatat

$ cat /tmp/testAwk/file3.txt
consequuntur magni dolores
sed quia non numquam

Quis autem vel eum iure reprehenderit

我正在尝试使用awk捕获--------------的两行之间的文本，并打印出与该模式匹配的文件名.

I am trying to use awk to capture the text between the two lines of -------------- and print out the names of files that match the pattern.

我从@Ed Morton收到了我以前的问题的精彩答复: https://stackoverflow.com/a/55507707/257233

I took the fantastic reply from @Ed Morton to my previous question: https://stackoverflow.com/a/55507707/257233

awk '{x=sub(/^-+$/,"")} f; x{f=!f}' *.txt

我试图对其进行调整，以打印出与模式匹配并缩进结果的那些文件的文件名.我无法弄清楚如何在awk中完成全部工作，因此最终在其中也添加了grep和sed.

I tried to adapt it to print out the file names of those files that match the pattern and indent the results. I couldn't work out how to do the whole job in awk, so I ended up with some grep and sed in there as well.

$ awk 'FNR==1{print FILENAME} {x=sub(/^-+$/,"---")} f; x{f=!f}' $(grep -E '^-+$' /tmp/testAwk/*.txt -l) | sed -re 's/^([^\/])/   \1/'
/tmp/testAwk/file1.txt
   important text one
   important text two
   ---
   important text three
   important text four
   ---
/tmp/testAwk/file2.txt
   important text one
   important text two
   ---
   important text three
   important text four
   ---

我可以仅使用awk来执行上述操作吗?

Can I do the above just with awk?

推荐答案

这就是我要这样做的方式，尤其是因为您的用例似乎正在发展，需要更多功能，因此将其塞入简短的单行代码中并不是最佳方法:

Here's how I'd do it, especially since your use case seems to be evolving to require more functionality so cramming it into a brief one-liner isn't the best approach:

$ cat tst.awk
FNR==1 { delimCnt=inBlock=block="" }
/^-+$/ {
    inBlock = (++delimCnt % 2)
    if ( !inBlock ) {
        if (delimCnt > 1) {
            if (delimCnt == 2) {
                print FILENAME
            }
            print block "   ---"
        }
        block = ""
    }
    next
}
inBlock { block = block "   " $0 ORS }

.

$ awk -f tst.awk file1.txt file2.txt file3.txt
file1.txt
   important text one
   important text two
   ---
   important text three
   important text four
   ---
file2.txt
   important text one
   important text two
   ---
   important text three
   important text four
   ---

这篇关于打印与awk脚本匹配的文件名的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！