Java中的颜色类 [英] Color Class in Java

问题描述

我对Java中的awt Color类有疑问.

I have a question regarding the awt Color class in Java.

我目前正在使用类缩写，例如Color.RED和Color.BLACK.我还列出了三个整数，例如:

I am currently using the class abbreviations such as Color.RED and Color.BLACK. I also have a list of three integers such as the following:

int var1 = 0
int var2 = 0
int var3 = 255

是否存在将这些整数转换为适当的Java Color名称的方法?

Is there a method to convert these integers into the appropriate Java Color name?

推荐答案

在Java核心类中，没有办法使用单个方法来完成此操作.但是，您可以通过两种方式轻松地自己完成此操作.

There is no way to do this with a single method in the Java core classes. However, you can fairly easily do this yourself in two ways.

从您拥有的RGB值中创建一个新的Color:

Create a new Color out of the RGB values you have:

Color color = new Color(var1, var2, var3);

然后

1. 获取 Class 对象从Color类使用 .
2. 使用从中获取元素getEnumConstants() .
3. 使用 Arrays.stream()
4. 通过调用 toArray() 将流转换为数组.
5. 使用[0]获取该数组的第一个元素.如果没有预定义的颜色与您的颜色匹配，则会抛出ArrayIndexOutOfBoundsException.
6. 通过 Enum获取该颜色的名称的 toString() .

1. Get the Class object from the Color class with getClass().
2. Get the elements from that with getEnumConstants().
3. Stream it using Arrays.stream()
4. Filter it by calling filter(), so it only contains all the enum constants that equal the color you made (there should be either one or zero).
5. Use toArray() to turn the stream into an array.
6. Get the first element of that array with [0]. This will throw an ArrayIndexOutOfBoundsException if there isn't a predefined color matching your color.
7. Get the name of that color with Enum's toString().

String colorName = Arrays.stream(Color.getClass().getEnumConstants())
                         .filter(c -> c.equals(color))
                         .toArray()[0]
                         .toString();

第二种方式

首先，创建一个 HashMap Color中的>，其中包含您想要的所有颜色:

Second way

First, create a HashMap of Colors that contains all the colors you want:

HashMap<Color, String> colors = new HashMap<Color, String>();

colors.put(Color.BLACK,            "BLACK");
colors.put(Color.BLUE,             "BLUE");
colors.put(Color.CYAN,             "CYAN");
colors.put(Color.DARK_GRAY,        "DARK_GRAY");
colors.put(Color.GRAY,             "GRAY");
colors.put(Color.GREEN,            "GREEN");
colors.put(Color.LIGHT_GRAY,       "LIGHT_GRAY");
colors.put(Color.MAGENTA,          "MAGENTA");
colors.put(Color.ORANGE,           "ORANGE");
colors.put(Color.PINK,             "PINK");
colors.put(Color.RED,              "RED");
colors.put(Color.WHITE,            "WHITE");
colors.put(new Color(192, 0, 255), "PURPLE");
colors.put(new Color(0xBADA55),    "BADASS_GREEN");
colors.put(new Color(0, 0, 128),   "DARK_BLUE");

然后，从您拥有的RGB值中创建一个新的Color:

Then, create a new Color out of the RGB values you have:

Color color = new Color(var1, var2, var3);

最后， get 键color中colors中的值:

String colorName = colors.get(color);

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