matplotlib如何开始刻度线，从轴原点开始留有空间 [英] matplotlib how to start ticks leaving space from the axis origin

问题描述

我需要以简单的折线图的形式针对日期绘制非数字数据.我正在使用matplotlib.

I need to plot non-numeric data against dates as a simple line graph. I am using matplotlib.

这是一些示例代码.

import matplotlib.pyplot as plt

xticks=['Jan','Feb','Mar','April','May']
x=[1,2,3,4,5]
yticks = ['Windy', 'Sunny', 'Rainy', 'Cloudy', 'Snowy']
y=[2,1,3,5,4]

plt.plot(x,y,'bo') #.2,.1,.7,.8
plt.subplots_adjust(left =0.2)

plt.xticks(x,xticks)
plt.yticks(y,yticks)
plt.show()

我想开始刻度标签，从原点开始留一些空间.这样它们看起来不会很挤.我应该为此使用Fixedlocator吗?另外，我希望图形是一条线，显示每个点的标记，例如此示例. 我该如何实现?

I want to start the tick labels leaving some space from the origin. So that they don't look very crammed. Should I be using Fixedlocator for this? Also I would like the graph to be a line showing markers for every point like in this example. How can I achieve this?

推荐答案

• 您可以通过使用ax.set_ylim设置较低的ylim来提升"图形.
• 可以使用marker = 'o'将标记点添加到绘图中 调用plt.plot的参数设置:
• You can "lift" the graph by setting a lower ylim with ax.set_ylim.
• Marker dots can be added to the plot using the marker = 'o' parameter setting in the call to plt.plot:

import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)

xticks=['Jan','Feb','Mar','April','May']
x=[1,2,3,4,5]
yticks = ['Windy', 'Sunny', 'Rainy', 'Cloudy', 'Snowy']
y=[2,1,3,5,4]

plt.plot(x,y,'b-', marker = 'o') #.2,.1,.7,.8
plt.subplots_adjust(left =0.2)

plt.xticks(x,xticks)
plt.yticks(y,yticks)
ax.set_ylim(0.5,max(y))
plt.show()

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