我将如何使用AngularJS NG重复使用Twitter的引导的脚手架？ [英] How would I use AngularJS ng-repeat with Twitter Bootstrap's scaffolding?

问题描述

我将如何使用AngularJS NG-重复来显示以下HTML（Twitter的引导脚手架）？从本质上讲，每个第三个记录，我需要关闭＆LT; / DIV＆GT; ，打印＆LT; HR＆GT; ，然后打开另一个＆LT; D​​IV CLASS =span4＆GT;

How would I use AngularJS ng-repeat to display the following HTML (Twitter Bootstrap Scaffolding)? Essentially, every third record I need to close the </div>, print an <hr>, then open another <div class="span4">

    <div class="row">
      <div class="span4">
        <h3>
          Project A
        </h3>
      </div>
      <div class="span4">
        <h3>
          Project B
        </h3>
      </div>
      <div class="span4">
        <h3>
          Project C
        </h3>
      </div>
    </div>

    <hr>

    <div class="row">
      <div class="span4">
        <h3>
          Project D
        </h3>
      </div>
      <div class="span4">
        <h3>
          Lab Title
        </h3>
      </div>
      <div class="span4">
        <h3>
          Project E
        </h3>
      </div>
    </div>

我已经为code演示小提琴。结果
http://jsfiddle.net/ADukg/261/

推荐答案

一个更优雅的方式是使用视图模型提供了分块集合，然后让视图处理它像

A more elegant way is to use the view model to provide a chunked collection and then let the view handle it like

<div ng-controller="Controller">
    Projects <input ng-model="projects"></input>
    <hr/>
    <div ng-repeat="row in rows">
        <div ng-repeat="project in row">
            Projects {{project}}
        </div>
        <hr/>
    </div>
</div>​

和CoffeeScript的将是pretty简单

and the coffeescript is pretty simple

# Break up an array into even sized chunks.
chunk = (a,s)->
    if a.length == 0
        []
    else               
        ( a[i..i+s-1] for i in [0..a.length - 1 ] by s)

@Controller = ($scope)->
    $scope.projects = "ABCDEF"

    $scope.$watch "projects", ->      
       $scope.rows = chunk $scope.projects.split(""), 3

angular.bootstrap(document, []);

http://jsfiddle.net/ADukg/370/

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