bash字符串与多个正确值进行比较 [英] bash string compare to multiple correct values

问题描述

我有以下bashscript:

i have the following piece of bashscript:

function get_cms {
    echo "input cms name"
    read cms
    cms=${cms,,}
    if [ "$cms" != "wordpress" && "$cms" != "meganto" && "$cms" != "typo3" ]; then
        get_cms
    fi
}

但是无论我输入什么(正确和错误的值)，它都不会再调用该函数，因为我只想允许这3个输入之一. 我已经尝试过||与[ var != value ] or [ var != value1 ] or [ var != value1 ] 但没有任何效果. 有人可以指出我正确的方向吗?

But no matter what i input (correct and incorrect values) it never calls the function again, because I only want to allow 1 of those 3 inputs. I have tried it with || with [ var != value ] or [ var != value1 ] or [ var != value1 ] but nothing works. Can someone point me in the right direction?

推荐答案

而不是说:

if [ "$cms" != "wordpress" && "$cms" != "meganto" && "$cms" != "typo3" ]; then

说:

if [[ "$cms" != "wordpress" && "$cms" != "meganto" && "$cms" != "typo3" ]]; then

您可能还想参考有条件的构造.

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