变量变量分配错误-“未找到命令"； [英] Variable variable assignment error -"command not found"

问题描述

运行脚本时，出现以下错误.请问我在这里做错了什么?任何帮助表示赞赏-Bash新手

When I run the script I get the following errors. What am I doing wrong here please? Any help appreciated- Bash Newbie

错误:

line 12: 0=1: command not found
line 13: 0=1: command not found

我的脚本:

count_raw=0
avg_raw=0

$count_raw=1
$avg_raw=1

echo "count_raw=$count_raw"
echo "avg_raw=$avg_raw"

推荐答案

=是赋值运算符，当发现它是免费的并且$拥有变量的值(不仅在美国，而且在bash中).

= is an assignment operator when found free and $ holds value (not only in USA but in bash too) of a variable.

因此，当您说:$var=1时，您实际上是在尝试在bash中键入随机字符串(在您的情况下为0=1)，而bash不喜欢那样.请看下面的单行代码，该代码显示了一个示例，您可以在其中键入$var=1，bash可以对其进行处理:

So when you say: $var=1, you're essentially trying to type a random string (0=1 in your case) in bash and bash doesn't like that. Look at the one-liner below that shows one example where you'd type in $var=1 and bash would be able to process it:

var=1; if [[ $var=1 ]]; then printf "Congrats! You have learned the difference between variable assignment and variable comparison in the ${var}st attempt.\n"; fi;

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