我可以使用sed在bash中操作变量吗? [英] Can I use sed to manipulate a variable in bash?

问题描述

在我的程序中，我想首先获取用户输入，并在每个/之前插入一个\ 所以我写了这个，但是没用.

In my program, I would like to first get the user input, and insert a \ before each / so I write this, but it doesn't work.

echo "input a website"
read website

sed '/\//i\/' $website

推荐答案

尝试一下:

website=$(sed 's|/|\\/|g' <<< $website)

Bash实际上支持:

Bash actually supports this sort of replacement natively:

${parameter/pattern/string} —将pattern的第一个匹配项替换为string.
${parameter//pattern/string} —将pattern的所有匹配项替换为string.

${parameter/pattern/string} — replace the first match of pattern with string.
${parameter//pattern/string} — replace all matches of pattern with string.

因此，您可以这样做:

website=${website////\\/}

说明:

website=${website // / / \\/}
                  ^  ^ ^  ^
                  |  | |  |
                  |  | |  string, '\' needs to be backslashed
                  |  | delimiter
                  |  pattern
                  replace globally

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