sed多行删除模式 [英] sed multiline delete with pattern

问题描述

我想删除模式中所有多行出现的情况

I want to delete all multiline occurences of a pattern like

  {START-TAG
  foo bar
  ID: 111
  foo bar
  END-TAG}

  {START-TAG
  foo bar
  ID: 222
  foo bar
  END-TAG}

  {START-TAG
  foo bar
  ID: 333
  foo bar
  END-TAG}

我要删除START-TAG和END-TAG之间包含特定ID的所有部分.

I want to delete all portions between START-TAG and END-TAG that contain specific IDs.

因此，要删除ID:222，只能保留以下内容:

So to delete ID: 222 only this would remain:

  {START-TAG
  foo bar 2
  ID: 111
  foo bar 3
  END-TAG}


  {START-TAG
  foo bar 2
  ID: 333
  foo bar 3
  END-TAG}

我有一个应该删除的ID黑名单.

I have a blacklist of IDs that should be removed.

我假设一个非常简单的多行sed regex脚本可以做到这一点.有人可以帮忙吗?

I assume a quite simple multiline sed regex script would do it. Can anyone help?

它与问题非常相似: sed多行替换，但不相同.

It is very similar to Question: sed multiline replace but not the same.

推荐答案

您可以使用以下内容:

sed '/{START-TAG/{:a;N;/END-TAG}/!ba};/ID: 222/d' data.txt

故障:

/{START-TAG/ { # Match '{START-TAG'
:a             # Create label a
N              # Read next line into pattern space
/END-TAG}/!    # If not matching 'END-TAG}'...
           ba  # Then goto a
}              # End /{START-TAG/ block
/ID: 222/d     # If pattern space matched 'ID: 222' then delete it. 

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