从bash脚本循环遍历多个文件扩展名 [英] Loop over multiple file extensions from bash script

问题描述

我需要在Linux终端中使用的bash脚本，该脚本应类似于:

I need a bash script for use in the Linux terminal which should go something like:

#!/bin/bash 

for textgrid_file in ./*.TextGrid and for wav_file in ./*.wav
do 
   praat --run pitch.praat "$textgrid_file" "$wav_file" >> output.txt
done

即我需要遍历具有扩展名.textgrid和.wav的文件对，因为在我的Praat脚本pitch.praat中，我有两个参数要传递.如何通过bash脚本实现它?

I.e. I need to iterate through pairs of files with extensions .textgrid and .wav because in my Praat script pitch.praat I have two arguments to pass. How can I implement it via bash scripting?

推荐答案

您可以使用数组支持来遍历第一个glob模式并使用数组中的第二个文件:

You can use an array support to iterate over first glob pattern and use 2nd file from array:

waves=(*.wav)

k=0
for textgrid_file in *.TextGrid; do
    praat --run pitch.praat "$textgrid_file" "${waves[k++]}" >> output.txt
done

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