如何在Bash脚本退出之前运行命令? [英] How to run a command before a Bash script exits?

问题描述

如果Bash脚本具有set -e，并且脚本中的命令返回错误，那么如何在脚本退出之前进行一些清除?

If a Bash script has set -e, and a command in the script returns an error, how can I do some cleanup before the script exits?

例如:

#!/bin/bash
set -e
mkdir /tmp/foo
# ... do stuff ...
rm -r /tmp/foo

即使... do stuff ...中的命令之一失败，我如何确保将/tmp/foo删除?

How can I ensure that /tmp/foo is removed, even if one of the commands in ... do stuff ... fails?

推荐答案

以下是使用陷阱的示例:

Here's an example of using trap:

#!/bin/bash -e

function cleanup {
  echo "Removing /tmp/foo"
  rm  -r /tmp/foo
}

trap cleanup EXIT
mkdir /tmp/foo
asdffdsa #Fails

输出:

dbrown@luxury:~ $ sh traptest
t: line 9: asdffdsa: command not found
Removing /tmp/foo
dbrown@luxury:~ $

请注意，即使asdffdsa行失败，清理仍会执行.

Notice that even though the asdffdsa line failed, the cleanup still was executed.

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