在bash中串联字符串会覆盖它们 [英] Concatenating strings in bash overwrites them

问题描述

我正在解析mysql命令的查询结果(带有--table参数)

I'm parsing query results from a mysql command (with the --table parameter)

local records=`echo "${query}" | $MYSQL -u $MyUSER -h $MyHOST -p$MyPASS --table`

查询成功运行，并且我收到了很好的数据.

The query is run successfully, and I receive good data.

然后我遍历此数据:

for data in $records ;
do
    test+=$data
done

代码更广泛，但是基本上就是这样. 但是Bash会将每个空格都视为分隔符，这对于文本字段来说是个问题.

The code is more extensive, but this is basically it. Bash sees every space as a separator though, and that's a problem for text fields.

所以我将它们串联起来.但是当我喂bash这些数据时:

So I just concatenate them. But when I feed bash this data:

*URL*
host:
test.url.com
pass:
anothertest

http://www.test.com

它将其连接为类似的内容:

It concatenates it to something like:

pass:test.url.com.com

好像不是在串联，而是在覆盖. 这可能是回车的问题吗?

As if it's not concatenating, but overwriting. Is this maybe some carriage return problem?

推荐答案

我对从curl命令检索的stderr输出有相同的问题.我发现输出包含需要删除的回车符.对于上面的示例，可以使用tr工具完成此操作:

I had the same issue with the stderr output retrieved from the curl command. I found that the output contains carriage return that needs to be removed. For the example above this could be done using the tr tool:

for data in $records ;
do
    data=$(echo "$data" | tr -d '\r')
    test+="$data"
done

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