为什么在bash字符串相等性测试中出现意外的运算符错误? [英] Why am i getting an unexpected operator error in bash string equality test?
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问题描述
第四行的错误在哪里?
if [ $bn == README ]; then
如果我将其写为
if [ $bn == README ]
then
或
if [ "$bn" == "README" ]; then
上下文:
for fi in /etc/uwsgi/apps-available/*
do
bn=`basename $fi .ini`
if [ $bn == "README" ]
then
echo "~ ***#*** ~"
else
echo "## Shortend for convience ##"
fi
done
推荐答案
您不能将==用于单括号比较([]).请改用single =.另外,您必须引用变量以防止扩展.
You can't use == for single bracket comparisons ([ ]). Use single = instead. Also you must quote the variables to prevent expansion.
if [ "$bn" = README ]; then
如果使用[[]],则可能适用,并且不需要引用第一个参数:
If you use [[ ]], that could apply and you wouldn't need to quote the first argument:
if [[ $bn == README ]]; then
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