使用bash从文本文件中删除ANSI颜色代码 [英] Remove ANSI color codes from a text file using bash

问题描述

我有一个可以运行并输出到文本文件的bash脚本，但是它还包含了它所使用的颜色代码，我想知道如何从文件中删除它们，即

I have a bash script that runs and outputs to a text file however the colour codes it uses are also included what i'd like to know is how to remove them from the file, ie

^[[38;1;32mHello^[[39m
^[[38;1;31mUser^[[39m

所以我只想留下Hello和User

so I just want to be left with Hello and User

推荐答案

sed -r "s/\x1B\[(([0-9]{1,2})?(;)?([0-9]{1,2})?)?[m,K,H,f,J]//g" file_name

此命令从文件中删除特殊字符和颜色代码

this command removes the special characters and color codes from the file

这些是一些ANSI代码: ESC[#;#H or ESC[#;#f将光标移至行#的列# ESC[2J清除屏幕和主光标 ESC[K清除到行尾，

these are some of ANSI codes: ESC[#;#H or ESC[#;#f moves cursor to line #, column # ESC[2J clear screen and home cursor ESC[K clear to end of line,

注意，如果代码清晰，则既没有数字也没有分号;

note in case of clear code there is neither number nor semicolon ;

同意以下评论: 如果数字多于2位，请使用:

agree with below comment: if the numbers are more than 2 digit kindly use this:

sed -r "s/\x1B\[(([0-9]+)(;[0-9]+)*)?[m,K,H,f,J]//g" filename

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