如何在单个循环的每次迭代中从多个文件的每一个中读取一行? [英] How to read a line from each of several files in each iteration of a single loop?

问题描述

我需要在一个循环中读取多个文件.我有一个带有X坐标的文件，一个带有Y坐标的文件，一个带有这些坐标的字符的文件.

I need to read from multiple file in one loop. I have one file with X coords, one file with Y coords and one file with chars on those coords.

现在我使用paste将这些文件放在一起，然后在while循环中使用cut这样将它们分开:

For now I use paste to put these files together, and then in a while loop use cut to separate them like this:

paste x-file y-file char-file | while -r line; do
    Y=$(echo "$line" | cut -d\  -f1)
    X=$(echo "$line" | cut -d\  -f2)
    CHAR=$(echo "$line" | cut -d\  -f3)
done

但是问题是它真的很慢(一次又一次地调用cut).

but the problem with this is that it's really slow (calling cut again and again).

在加快速度的同时，如何在每个循环中在$Y，$X和$CHAR中具有适当的值?

How should I do this to have in each loop proper values in $Y, $X and $CHAR while speeding things up?

推荐答案

我不确定在没有paste的情况下怎么做，但是您可以避免cut在一个read中分配所有变量:

I'm not sure how to do it without paste, but you can avoid cut assigning all variables in one read:

while read -r X Y CHAR; do
    echo "X = $X; Y = $Y; CHAR = $CHAR";
done < "$file"

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