伪装成bash中的tty来执行任何命令 [英] Pretend to be a tty in bash for any command

问题描述

每当我使用grep并将其通过管道传输到其他程序时，就不会使用--color选项.我知道我可以使用--color=always，但是它还提供了一些其他命令，我希望获得该命令的确切输出，就像我在tty中一样.

所以我的问题是，是否有可能欺骗某个命令以使其认为该命令在tty中运行?

例如，运行

grep --color word file # Outputs some colors
grep --color word file | cat # Doesn't output any colors

我希望能够写一些类似的东西:

IS_TTY=TRUE grep --color word file | cat  # Outputs some colors

空-在以下环境下运行进程和应用程序伪终端(PTY)，但是从我在文档中可以看到的内容来看，我不确定它是否可以解决我的问题

解决方案

还有其他一些Stack Overflow答案所概述的选项(请参阅评论).我会在这里总结一下:

1. 使用script + printf ，不需要其他依赖项:

   0<&- script -qefc "ls --color=auto" /dev/null | cat
   

   或制作一个bash函数faketty对其进行封装:

   faketty () {
       script -qfce "$(printf "%q " "$@")"
   }
   faketty ls --color=auto | cat  
   

   或者在鱼壳中:

   function faketty
       script -qefc "(printf "%q " "$argv")"
   end
   faketty ls --color=auto | cat 
   

   (信用转到此 http://linux.die.net/man/1/script

2. 使用unbuffer命令(作为expect命令套件的一部分)，不幸的是，这需要安装50mb +，但这是最简单的解决方案:

   sudo apt-get install expect-dev
   unbuffer -p ls --color=auto | cat  
   

   或者，如果您使用鱼壳:

   function faketty
       unbuffer -p $argv
   end
   faketty ls --color=auto | cat 
   

   http://linux.die.net/man/1/unbuffer

这是一篇很棒的文章，介绍了TTY的工作方式以及什么是Pseudo-TTY(PTY)，如果您想了解linux shell如何与文件描述符一起传递输入，输出和信号，那么值得一看. . http://www.linusakesson.net/programming/tty/index.php

Whenever I use grep, and I pipe it to an other program, the --color option is not respected. I know I could use --color=always, but It also comes up with some other commands that I would like to get the exact output of that command as the output I would get if I was in a tty.

So my question is, is it possible to trick a command into thinking that the command is run inside a tty ?

For example, running

grep --color word file # Outputs some colors
grep --color word file | cat # Doesn't output any colors

I'd like to be able to write something like :

IS_TTY=TRUE grep --color word file | cat  # Outputs some colors

This question seems to have a tool that might do what I want :empty - run processes and applications under pseudo-terminal (PTY), but from what I could read in the docs, I'm not sure it can help for my problem

解决方案

There are a number of options, as outlined by several other Stack Overflow answers (see Caarlos's comment). I'll summarize them here though:

1. Use script + printf, requires no extra dependencies:

   0<&- script -qefc "ls --color=auto" /dev/null | cat
   

   Or make a bash function faketty to encapsulate it:

   faketty () {
       script -qfce "$(printf "%q " "$@")"
   }
   faketty ls --color=auto | cat  
   

   Or in the fish shell:

   function faketty
       script -qefc "(printf "%q " "$argv")"
   end
   faketty ls --color=auto | cat 
   

   (credit goes to this answer)

   http://linux.die.net/man/1/script

2. Use the unbuffer command (as part of the expect suite of commands), unfortunately this requires a 50mb+ install, but it's the easiest solution:

   sudo apt-get install expect-dev
   unbuffer -p ls --color=auto | cat  
   

   Or if you use the fish shell:

   function faketty
       unbuffer -p $argv
   end
   faketty ls --color=auto | cat 
   

   http://linux.die.net/man/1/unbuffer

This is a great article on how TTYs work and what Pseudo-TTYs (PTYs) are, it's worth taking a look at if you want to understand how the linux shell works with file descriptors to pass around input, output, and signals. http://www.linusakesson.net/programming/tty/index.php

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