将Bash脚本参数$ @存储在变量中 [英] Store Bash script arguments $@ in a variable

问题描述

如何在保持其属性的同时将$@存储在变量中?

How can I store $@ in a variable while keeping its properties?

即使在所有可能的情况下使用$@或我自己的变量，我也希望获得完全相同的行为.

I want to obtain exactly the same behavior even if I use $@ or my own variable in all possible situations.

以下尝试无效:

args=$@
args2="$@"        # the arguments are combined (see the last output paragraph)

我使用以下代码对它们进行了测试:

I tested them using the following line:

s.sh A B="       " C

s.sh

#!/bin/bash

args=$@
args2="$@"
#args3 = ? - TODO

echo $args
echo $args2
echo $@
#echo $args3   

echo

echo "$args"
echo "$args2"
echo "$@"
#echo "$args3"

echo

java A $args
java A $args2
java A $@
#java A $args3

echo

java A "$args"
java A "$args2"
java A "$@"
#java A "$args3"

A.java

import java.util.Arrays;

public class A {
    public static void main(String args[]){
        System.out.println(args.length + ": " + Arrays.asList(args));
    }
}

实际输出:

A B= C
A B= C
A B= C

A B= C
A B=        C
A B=        C

3: [A, B=, C]
3: [A, B=, C]
3: [A, B=, C]

1: [A B= C]
1: [A B=        C]
3: [A, B=       , C]

预期输出(如果将TODO替换为解决方案)并且启用了echo

Expected output (if TODO is replaced by a solution) and echos are enabled

A B= C
A B= C
A B= C
A B= C

A B= C
A B=        C
A B=        C
A B=        C

3: [A, B=, C]
3: [A, B=, C]
3: [A, B=, C]
3: [A, B=, C]

1: [A B= C]
1: [A B=        C]
3: [A, B=       , C]
3: [A, B=       , C]

推荐答案

您可以将其存储在数组中:

You can store it in an array:

args=("$@")

然后您可以使用索引"${args[index]}"访问每个参数，并使用"${args[@]}"一次访问所有参数.

then you can access each of the arguments with index: "${args[index]}" and all arguments at once with "${args[@]}".

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