如何仅打印BASH中的唯一行? [英] How to print only the unique lines in BASH?

问题描述

如何仅打印那些在文件中仅出现一次的行?例如，给定此文件:

How can I print only those lines that appear exactly once in a file? E.g., given this file:

mountain
forest
mountain
eagle

输出将是这样，因为行mountain出现了两次:

The output would be this, because the line mountain appears twice:

forest
eagle

• 如有必要，可以对行进行排序.

推荐答案

使用awk:

awk '{!seen[$0]++};END{for(i in seen) if(seen[i]==1)print i}' file
eagle
forest

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