循环从文件中查找应用程序并使用adb shell将其拉出 [英] Loop to find an app from a file and pull it with adb shell

问题描述

我从bash开始，正在编写一个读取文件的脚本，在android设备中搜索每一行的信息(文件的每一行都是设备上安装的应用的名称)

I'm beginning with bash, I'm writing a script that read a file, search an information in an android device for each line (each line of the file is the name of an app installed on the device)

#!/bin/bash
filename="$1"
while read -r line
do
    name="$line"
    echo "App : - $name" | adb shell pm path $name

done < "$filename"

这是该脚本的结果

package:/data/app/com.naver.linewebtoon-1/base.apk
package:/data/app/com.game5mobile.lineandwater-2/base.apk

如何获取每个结果行作为其他函数的参数

How can I get each result line as a parameter for an other function

adb shell cat /data/app/com.naver.linewebtoon-1/base.apk > app1.apk 
adb shell cat /data/app/com.game5mobile.lineandwater-2/base.apk > app2.apk

推荐答案

echo "App : - $name" | adb shell pm path $name将调用adb作为命令，将echo的输出发送到其标准输入.仅仅回显组成的命令将无法实现您的目标.

echo "App : - $name" | adb shell pm path $name would invoke adb as a command, sending echo's output to its standard input. That won't achieve your goal of just echoing the composed command.

使用IFS读取文件中的定界数据，并打印出如下组成的命令:

Use IFS to read the delimited data in your file and print out the composed command like this:

#!/bin/bash
filename="$1"
count=0
while IFS=: read -r _ path  # ignore the first field by reading it into a dummy variable
do
    printf '%s\n' "adb shell cat $path > app$((++count)).apk"
done < "$filename"

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