删除最后一个字符串字符串 [英] remove last characters string batch

问题描述

您好，我需要在txt文件中生成图像列表，但是我必须删除最后一个字符并删除重复项

hello I need to generate list of images in a txt file, but I have to remove the last character and delete duplicates

示例

SDFDFDF_1.jpg
SDFDFDF_2.jpg
THGGHFG_1.jpg
THGGHFG_2.jpg

，并且必须保留在txt列表中

and would have to stay that way in txt list

SDFDFDF
THGGHFG

我的代码仅删除.jpg

my code removes only .jpg

@echo off
if exist "sku.txt" del "sku.txt"
for /f "delims=" %%f in ('dir *.jpg /b') do echo %%~nf >> sku.txt

推荐答案

如果启用了扩展名，则应该可以使用:

If extensions are enabled, this should work:

@echo off
if exist "sku.txt" del "sku.txt"
setlocal enabledelayedexpansion
set list=
for /f "usebackq delims=" %%f in (`dir /b *.jpg`) do (
  set xx=%%~nf
  set candidate=!xx:~0,-2!
  set n=0
  for %%i in (!list!) do (
    if "!candidate!"=="%%i" (
      set n=1
    )
  )
  if !n! EQU 0 (
    set list=!list! !candidate!
    echo !candidate! >> sku.txt
  )
)

endlocal

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