非阻塞批处理文件执行 [英] Non-blocking batch file execution

问题描述

我在批处理文件中具有以下命令:

I have the following commands in a batch file:

"C:\MI2\Stream\bin\Debug\Stream.exe" 19
"C:\MI2\Stream\bin\Debug\Stream.exe" 20
"C:\MI2\Stream\bin\Debug\Stream.exe" 21
"C:\MI2\Stream\bin\Debug\Stream.exe" 23
"C:\MI2\Stream\bin\Debug\Stream.exe" 25

我正在尝试执行我创建的应用程序的5个实例，并为每个实例传递不同的参数.我的目标是，当我运行此批处理文件时，它将启动该应用程序的5个实例，并为每个实例加载一个UI组件.最终，我将使它变得更加优雅，并在其周围放置一个包装器应用程序，但现在我只希望它们同时运行.

I'm attempting to execute 5 instances of an application I created, passing in a different param to each. My goal is that when I run this batch file, it launches the 5 instances of this app, loading a UI component for each. Eventually I will make this more elegant, and put a wrapper app around this, but for now i just want these to run simultaneously.

问题是，当我启动此批处理文件时，它将执行第一行并加载UI.而已.它不会继续前进到第二行.有想法吗?

The problem is, when I launch this batch file, it executes the first line, loading the UI. That's it. It doesn't move on to the second line. Thoughts?

编辑以添加-我当然可以在单独的批处理文件中执行此操作，但是我希望一键启动. 斯科特

Edit to Add - I could certainly do this from separate batch files, but I'd like to have one-click launching. Scott

推荐答案

您可以使用

You can use start:

start "" "C:\MI2\Stream\bin\Debug\Stream.exe" 19
start "" "C:\MI2\Stream\bin\Debug\Stream.exe" 20
start "" "C:\MI2\Stream\bin\Debug\Stream.exe" 21
start "" "C:\MI2\Stream\bin\Debug\Stream.exe" 23
start "" "C:\MI2\Stream\bin\Debug\Stream.exe" 25

第一个参数是创建的命令行窗口的标题，我们不在乎，因此可以将其保留为空.

The first argument is the title of the created command line window, which we don't care about, so it can be left empty.

更好的方法是使用for:

forr %i in (19, 20, 21, 23, 25) do start "" "C:\MI2\Stream\bin\Debug\Stream.exe" %i

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