SET变量未在.BAT文件中读取 [英] SET variable not being read in .BAT file

问题描述

我有这个Windows批处理文件，无法正常使用.
基本上，我在一个位置有一个文件夹，我需要将其复制到另一个文件夹，但还要重命名新的文件夹名称.

I have this Windows batch file and I cannot get to work it properly.
Basically I have a folder in one location and I need to copy it to another folder, but to also have the new folder name renamed.

@Echo off
::
set 836147398 = @Taunus_A3
:: 
Echo Copying %836147398%
xcopy "C:\Users\arrona\Desktop\Update Mods\steamapps\workshop\content\107410\836147398" "C:\TCAFiles\Games\arma3exile\TCA.Mods\%836147398%" /s/h/e/k/f/c

所以我需要将333310405的文件夹内容复制到C:\TCAFiles\Games\arma3exile\TCA.Mods\，但作为@Taunus_A3文件夹名称.

So what I need is that the folder contents of 333310405 are copied to C:\TCAFiles\Games\arma3exile\TCA.Mods\, but as @Taunus_A3 folder name.

它将复制文件夹以及所有内容，但是不会读取变量.它将回显正在复制836147398"，而不回显正在复制@ Taunus_A3"

It will copy the folder over and all the contents, but it is not reading the variable. It will echo "Copying 836147398" not echoing "Copying @Taunus_A3"

推荐答案

1. 在set "varname=varvalue"命令中的=符号的两侧消除空格.
2. 避免使用前导数字命名变量.阅读命令行参数(参数):

1. Get rid of spaces on either side of the = sign in set "varname=varvalue" command.
2. Avoid naming variables with a leading number. Read Command Line arguments (Parameters):

尽管set "836147398=@Taunus_A3"是有效的命令，但echo %836147398%仍会显示

Although set "836147398=@Taunus_A3" is a valid command, echo %836147398% would display

• @Taunus_A3在命令提示符下，但是
批处理脚本中的
• 36147398，因为%8被计算为提供的第8个参数(在大多数情况下，假定为空字符串)，并且孤立的尾随%百分号在设计上被忽略.

• @Taunus_A3 in command prompt, but
• 36147398 in a batch script, because %8 is evaluated to the 8th supplied parameter (supposedly an empty string in most cases) and orphan trailing % percent sign is ignored by design.

解决方案:使用非密码前缀，例如_下划线如下:

Solution: use a non-cipher prefix, e.g. _ underscore as follows:

set "_836147398=@Taunus_A3"
echo %_836147398%

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