在批处理文件中访问未知数量的命令(参数) [英] Accessing unknown number of commands (parameters) in batch file

问题描述

这个有点难以解释，但我会尽力而为.

this one's a bit difficult to explain, but I'll do my best.

我正在通过字符串数组将目录列表传递到批处理文件中，该字符串数组是用Java创建的，然后使用Runtime.getRuntime().exec(commands)传递给.bat.我遇到的麻烦是关于访问命令数组的问题，命令数组的大小可能因执行而异.例如，在一次运行中，命令"可能包含以下内容:

I'm passing a list of directories into a batch file via a string array, which is created in Java and then passed into the .bat using Runtime.getRuntime().exec(commands). The trouble I am having is in regards to accessing the commands array, the size of which may vary from execution to execution. For example, during one run, "Commands" may contain the following:

{"cmd.exe"，"/C"，开始"，"program.bat"，"stringA"，"stringB"，"stringC"}

{"cmd.exe", "/C", "Start", "program.bat", "stringA", "stringB", "stringC"}

前四个元素用于调用批处理文件，因此只有字符串A，B和C作为参数传递到批处理文件(program.bat)中.但是，在下一次运行时，命令"可能看起来像这样:

The first four elements are used to call the batch file, so only strings A, B, and C are passed into the batch file (program.bat) as parameters. However, on the next run, "commands" may look like this:

{"cmd.exe"，"/C"，开始"，"program.bat"，"stringA"，"stringB"，"stringC"，stringD，stringE}

{"cmd.exe", "/C", "Start", "program.bat", "stringA", "stringB", "stringC", stringD, stringE}

如您所见，参数列表中又添加了两个字符串.我的问题是:在我的批处理文件中，我有这个:

As you can see, there are two more strings added to the parameters list. My question is this: In my batch file I have this:

::Get stringA (param 1)
set stringA=%1
::Get stringB (param 2)
set stringB=%2
::Get stringC (param 3)
set stringC=%3

这将使用三个字符串参数(来自第一个"commands"数组)，并将局部变量设置为传递给相应参数的任何值.我想知道是否有一种方法可以从批处理文件中确定参数的数量(例如，从第二个命令"数组)，并相应地设置/创建适当数量的局部变量.我主要关注Java，因此批处理文件对我来说还是一个新手.任何建议将不胜感激，因为我一直试图独自解决这一问题，但没有成功.

This takes the three string parameters (from the first "commands" array) and sets local variables to whatever values are passed in to the corresponding parameters. I am wondering if there is a way to determine the number of parameters (from the second "commands" array, for example) from within the batch file, and set/create the proper number of local variables accordingly. I focus primarily on Java, so batch files are still fairly new to me. Any suggestions will be very much appreciated, as I've been trying to figure this one out for a while on my own with no success.

推荐答案

如此处所述:

https://stackoverflow.com/a/14298769/955143

您可以从％1到％9进行读取，并使用SHIFT键从数组中删除第一个元素，然后将它们重新编号为新数字.

You can read by %1 to %9, and use SHIFT to delete the first element from the array, an then renummerate they to new numbers.

例如，％2变为％1，第10个元素变为第9个元素，您可以通过％9进行访问.

For instance, the %2 becomes %1, and the 10th element becomes the 9th, and you can acess it by %9.

由于读取的值变为空字符串，因此您已经到达数组的末尾

Since the read value become a empty string you have reached the end of the array

您可以编写一个循环(使用goto或for)来读取％1值，然后使用SHIFT将第二个元素旋转到第一个位置，并检查它是否不为空，然后重复该过程.

You can write a loop (with goto or for) to reade the %1 value, and use SHIFT to rotate the 2nd element to the first position, and check if it isn't empty, them repeat the process.

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