在批处理文件中使用定界符对文件名进行排序 [英] Sort file name with delimiter in batch file

问题描述

在Windows批处理脚本中，我需要按文件名列表的版本号排序，至少要最先. 文件名如下:

I need to sort the list of file names by their version number with least first, in windows batch script. The file names are like:

2_0_0to2_0_1
2_0_1_to2_0_2
...
2_0_12_to2_0_13
...

我尝试在Windows中进行dir和sort，但是似乎只查看char位置，在两位数的情况下不起作用.在Linux中，我使用以下命令完成了此操作:ls * .txt |排序-n -t _ -k1 -k2 -k3.如何在Windows上执行此操作.请帮忙.谢谢！

I've tried dir and sort in Windows but it seems to only look at char positions which wouldn't work in the case of double digits. In Linux, I've done this with: ls *.txt | sort -n -t _ -k1 -k2 -k3. How to do this on Windows. Please help. Thanks!

推荐答案

尝试一下:

@ECHO OFF &SETLOCAL ENABLEDELAYEDEXPANSION
FOR %%x IN (*) DO (
    FOR /f "tokens=1-6delims=_to" %%a IN ("%%~x") DO (
        SET "g1=0%%a"
        SET "g2=0%%b"
        SET "g3=0%%c"
        SET "g4=0%%d"
        SET "g5=0%%e"
        SET "g6=0%%f"
        SET "$!g1:~-2!!g2:~-2!!g3:~-2!!g4:~-2!!g5:~-2!!g6:~-2!=%%~x"
    )
)
FOR /f "tokens=2delims==" %%a IN ('set "$"') DO ECHO %%~a

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