获取变量中缺少指定文件的文件夹路径 [英] Get a folder path where is missing specified file into variable

问题描述

假设我有两个文件夹一个.

MyFolder \ Folder1 \-包含 .class 和 .java 文件

MyFolder\Folder1\ - contains .class and .java file

MyFolder \ Folder2 \-仅包含 .class 文件

MyFolder\Folder2\ - contains only .class file

问题是，是否可以使批处理文件检测(MyFolder)中缺少.java文件的文件夹，然后将路径放入变量中.

The question is, if you can make the batch file detect the folder in (MyFolder) where is a .java file missing and put the path into a variable.

类似的东西:

Something like:

在MyFolder \中查找没有* .java文件的子文件夹/-并且以某种方式将文件夹路径放入变量

find sub/folder with no *.java files in MyFolder\ <-and somehow to put the folder path into a variable

有人知道脚本的外观吗? 感谢每个人的帮助.

Does anyone know what would the script look like? Thanks to everybody that will help.

推荐答案

这里是一个想法，您可以对其进行处理以使其适合您的需求:

Here is an idea, you can work on it to make it suit your needs:

Setlocal EnableDelayedExpansion
for /D %%f in (MyFolder\*) do if not exist %%f\*.java (
    set nonJavaFolder=%%f
)
echo !nonJavaFolder!

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