在目录中的XML文件中搜索特定的字符串，然后使用bat脚本执行复制操作 [英] Search XML files in directory for specific string then do copy action using bat script

问题描述

我是批处理脚本的新手，因此，如果可能的话，我将感谢您提出评论的解决方案. 我正在寻找一个蝙蝠脚本，它将在包含XML文件的设置目录c:\中搜索包含"xyz"字符串(在其中而不是在其文件名中)的文件.找到带有"xyz"的文件后，应将其复制到另一个位置c:\ out. 出于说明目的，所有XML文件都具有相同的结构，并且字符串(应搜索文件)在标记内.

I'm new to batch scripts so I would appreciate commented solution if possible. I'm looking for a bat script that would search set directory c:\in containing XML files for files that contain "xyz" string (in them, not in their filename). Once the file with "xyz" is found it should be copied to another location c:\out . For illustration purposes all of XML files have the same structure and the string (that files should be search for) is within the tag .

推荐答案

@ECHO OFF
SETLOCAL
SET "sourcedir=U:\sourcedir"
SET "destdir=U:\destdir"
FOR /f "delims=" %%a IN ('findstr /m /L "xyz" "%sourcedir%\*.xml"') DO (
 echo(COPY "%%a" "%destdir%\%%~nxa"
)

GOTO :EOF

您需要根据自己的情况更改sourcedir和destdir的设置.

You would need to change the settings of sourcedir and destdir to suit your circumstances.

所需的COPY命令仅被ECHO用于测试目的. 确认命令正确无误后，将ECHO(COPY更改为COPY以实际复制文件.附加>nul以禁止显示报告消息(例如1 file copied)

The required COPY commands are merely ECHOed for testing purposes. After you've verified that the commands are correct, change ECHO(COPY to COPY to actually copy the files. Append >nul to suppress report messages (eg. 1 file copied)

只需将findstr的输出收集到%%a中，以在%sourcedir%\*.xml中搜索文字xyz. /m开关输出找到的包含字符串的文件名.使用~nxa构造适当的copy命令以仅选择名称和扩展名.

simply, gather the output of findstr searching for literal xyz in %sourcedir%\*.xml into %%a. The /m switch outputs the filenames found containing the string. Construct the appropriate copy command using ~nxa to select just the name and extension.

这篇关于在目录中的XML文件中搜索特定的字符串，然后使用bat脚本执行复制操作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！