如何从标签中获取文本，但忽略其他子标签 [英] how to get text from within a tag, but ignore other child tags

问题描述

我正在煮漂亮的汤. 我有一个html字符串:

I am working with beautiful soup. I have a html string:

<div><b>ignore this</b>get this</div>

如何在忽略"忽略此"

谢谢

推荐答案

您可以获取div文本，而不必递归检索子文本:

You can get the div text just not recursively retrieving the children texts:

>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<div><b>ignore this</b>get this</div>')
>>> soup.div.find(text=True, recursive=False)
u'get this'

这与文本相对于孩子的位置无关:

This works independently of the position of the text with respect of the children:

>>> soup = BeautifulSoup('<div>get this<b>ignore this</b></div>')
>>> soup.div.find(text=True, recursive=False)
u'get this'

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