urllib.error.URLError:< urlopen错误[Errno 11002] getaddrinfo失败&gt ;? [英] urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>？

问题描述

所以，我的代码只有4行.我正在尝试连接到一个网站，此后我想做的事无关紧要，因为没有其他代码就出现了错误.

So, My code is only 4 lines. I am trying to connect to a website, what I am trying to do after that is irrelevant because the error arised without the other codes.

import urllib.request
from bs4 import BeautifulSoup 

html=urllib.request.urlopen('http://python-data.dr-chuck.net/known_by_Fikret.html').read()
soup=BeautifulSoup(html,'html.parser')

和错误(简要总结为一个):

and the error(succinctly summarized one):

for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11002] getaddrinfo failed
During handling of the above exception, another exception occurred:
urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>

这是我尝试过的.

1. 我在Google上搜索了返回"urlopen错误[Errno 11002]的错误"，尤其是在stackoverflow上，没有返回任何有用的信息(实际上，对这个错误11002的询问不多).
2. 因此，然后我尝试替换网站参数(即" http://python- urlopen函数中的data.dr-chuck.net/known_by_Fikret.html )和另一个网站"
3. 因此，我想这个错误与该特定网站本身有关.该网站是动态的，我的意思是它的内容将会改变，并且变成另一种完全不同的事物.但是我不仅仅知道描述我所见的东西.

1. I searched for the Error returned "urlopen error [Errno 11002]" on google and especially on stackoverflow, nothing helpful was returned(In fact there are not much question on this error 11002 was asked).
2. So Then I try to replace the website argument(i.e. "http://python-data.dr-chuck.net/known_by_Fikret.html" ) inside the urlopen function with another website "http://www.pythonlearn.com/code/urllinks.py". And it worked just fine. No error comes up.
3. So I guess this error must have something to do with this particular website per se. The website is somewhat dynamic, by which I mean its content will alter and change into another wholly different thing. But I have no more knowledge than just to descibe what I saw.

以及错误的更长和完整版本:

and the longer and full version of error:

Traceback (most recent call last):
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 1240, in do_open
h.request(req.get_method(), req.selector, req.data, headers)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 1083, in request
self._send_request(method, url, body, headers)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 1128, in _send_request
self.endheaders(body)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 1079, in endheaders
self._send_output(message_body)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 911, in _send_output
self.send(msg)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 854, in send
self.connect()
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 826, in connect
(self.host,self.port), self.timeout, self.source_address)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\socket.py", line 693, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\socket.py", line 732, in getaddrinfo
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11002] getaddrinfo failed

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
File "D:/baiduyundownload/Tempo/Active/Python/Python Examples/Fileanalysis11111.py", line 4, in <module>
html=urllib.request.urlopen('http://python-data.dr-chuck.net/known_by_Fikret.html').read()
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 162, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 465, in open
response = self._open(req, data)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 483, in _open
'_open', req)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 443, in _call_chain
result = func(*args)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 1268, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 1242, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>

推荐答案

这意味着您的DNS系统无法正常工作，或者您必须在网络上使用代理并且定义不正确.

This means that either your DNS system is not working correctly, or you have to use a proxy on your network and it isn't defined correctly.

如果需要使用代理，请将环境变量HTTP_PROXY(以及可选的HTTPS_PROXY)设置为网络的正确配置.格式为http://proxy.example.com:80;如果您的代理服务器需要用户名和密码，则应将其传递，例如:http://username:[e-mail]:80.

If you need to use a proxy, set the environment variable HTTP_PROXY (and optionally, HTTPS_PROXY) to the correct configuration for your network. The format is http://proxy.example.com:80; if your proxy needs a username and password, you should pass it in, like this: http://username:[e-mail]:80.

对于DNS问题，请尝试从命令行查找域.打开命令提示符，然后键入nslookup python-data.dr-chuck.net，然后查看它是否为您返回IP地址.

For DNS issues, try looking up the domain from the command line. Open a command prompt and type nslookup python-data.dr-chuck.net and see if it returns to you an IP address.

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