获取< a>的href < li>中的标签 [英] Getting the href of <a> tag which is in <li>

问题描述

如何获取给定代码中类"Subforum"下的所有标签的href?

How to get the href of the all the tag that is under the class "Subforum" in the given code?

<li class="subforum">
<a href="Link1">Link1 Text</a>
</li>
<li class="subforum">
<a href="Link2">Link2 Text</a>
</li>
<li class="subforum">
<a href="Link3">Link3 Text</a>
</li>

我已经尝试了这段代码，但是显然没有用.

I have tried this code but obviously it didn't work.

Bs = BeautifulSoup(requests.get(url).text,"lxml")
Class = Bs.findAll('li', {'class': 'subforum"'})
for Sub in Class:
    print(Link.get('href'))

推荐答案

href属于a标签，而不是li标签，请使用li.a获取a标签

The href belongs to a tag, not li tag, use li.a to get a tag

文档:使用标签名称进行导航

import bs4

html = '''<li class="subforum">
 <a href="Link1">Link1 Text</a>
 </li>
 <li class="subforum">
<a href="Link2">Link2 Text</a>
</li>
<li class="subforum">
<a href="Link3">Link3 Text</a>
</li>`<br>'''

soup = bs4.BeautifulSoup(html, 'lxml')
for li in soup.find_all(class_="subforum"):
    print(li.a.get('href'))

退出:

Link1
Link2
Link3

为什么要使用class_:

搜索具有特定CSS类的标签非常有用，但是CSS属性的名称class 在Python中是保留字.使用类作为关键字参数会出现语法错误.从Beautiful Soup 4.1.2开始，您可以使用关键字参数class_按CSS类进行搜索.

It’s very useful to search for a tag that has a certain CSS class, but the name of the CSS attribute, class, is a reserved word in Python. Using class as a keyword argument will give you a syntax error.As of Beautiful Soup 4.1.2, you can search by CSS class using the keyword argument class_.

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