登录到Sales navigator python selenium [英] sign in to Sales navigator python selenium

问题描述

我正在尝试完成一个简单的任务，即登录到销售导航器页面，此后，我可以继续尝试收集销售线索和客户数据，作为收集信息的练习.遵循此链接进行登录之后，我有了此脚本来完成任务

I am trying to achieve a simple task of signing into sales navigator page,after which I can proceed to try and scrap the leads and accounts data, as a exercise for scraping. Following this link for signing in, I have this script to achieve the task

    browser = webdriver.Firefox(executable_path=r'D:\geckodriver\geckodriver.exe')

    def login_linkedin(email_id,psswd):

        sales_url = "https://www.linkedin.com/sales/login"
        browser.get(sales_url)

        elem_username = browser.find_element_by_id("username")
        #elem_username = browser.find_element_by_name("session_key")
        elem_username.send_keys(email_id)
        elem_psswd = browser.find_element_by_id("password")
        #elem_psswd = browser.find_element_by_name("session_password")
        elem_psswd.send_keys(psswd)

        elem_signin = find_element_by_class_name("login__form_action_container ").click()

    if __name__ == "__main__":

        login_linkedin("la","la")

通过检查用户名，密码和登录按钮(如下所示)字段的每个元素，我试图通过名称，类名和ID查找该元素，但始终以未找到元素结束错误.我可能会缺少什么?

By inspecting each element of the fields of username, password and the sign in button (shown below), I tried to find the element by name, class name and id, but always end up with the element not found error. What could I be missing?

用户名元素

  <input id="username" name="session_key" type="text" aria-describedby="error-for-username" required="" validation="email|tel" autofocus="" aria-label="Email or Phone">

密码元素

  <input id="password" type="password" aria-describedby="error-for-password" name="session_password" required="" validation="password" aria-label="Password">

登录按钮元素

  <button class="btn__primary--large from__button--floating" type="submit" aria-label="Sign in">Sign in</button>

错误

Traceback (most recent call last):
File "D:\Freelancing\Scrap_sales_nav\code\my_code\scrap_accounts.py", line 40, in <module>
login_linkedin("la","la")
File "D:\Freelancing\Scrap_sales_nav\code\my_code\scrap_accounts.py", line 21, in login_linkedin
elem_username = browser.find_element_by_id("username")
File "C:\Python36\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 360, in find_element_by_id
return self.find_element(by=By.ID, value=id_)
File "C:\Python36\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 978, in find_element
'value': value})['value']
File "C:\Python36\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 321, in execute
self.error_handler.check_response(response)
File "C:\Python36\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: [id="username"]

推荐答案

问题是您要查找的是iframe，因此我们需要将硒指向iframe而不是标准网页.幸运的是，硒具有以下功能:switch_to_frame()

The issue is that what you're looking for is in an iFrame, we will therefore need to point selenium to the iframe instead of the standard webpage. Fortunately selenium has a function for this: switch_to_frame()

解决方案:

import time

browser = webdriver.Firefox(executable_path=r'D:\geckodriver\geckodriver.exe')

def login_linkedin(email_id, psswd):
        sales_url = "https://www.linkedin.com/sales/login"
        browser.get(sales_url)
        # sleeping to give the page time to load
        time.sleep(1)
        # the two lines below will put us into the iframe
        frame = browser.find_element_by_tag_name('iframe')
        browser.switch_to_frame(frame)
        # entering the username and password
        elem_username = browser.find_element_by_id("username")
        elem_username.send_keys(email_id)
        elem_psswd = browser.find_element_by_id("password")
        elem_psswd.send_keys(psswd)
        # no need for a variable name, we can just click
        browser.find_element_by_class_name("login__form_action_container ").click()

if __name__ == "__main__":
    login_linkedin('email_id', 'psswd')

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