力布局中的d3动态曲线 [英] d3 dynamic curved line in force layout
本文介绍了力布局中的d3动态曲线的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想要这样的力布局中的线具有动态贝塞尔曲线,例如 cytoscape示例,在d3中可以吗?请参见此 d3示例,但请使用arc. 我不知道算法,有人知道吗?
I'd like to have a dynamic bezier curve for the line in a force layout like this cytoscape example, is possible in d3? see this d3 example but use arc. I have no idea of the algorithm, someone has an idea?
推荐答案
我已经看到 cytoscape 库,并且可以使用此algorytm
i've see the cytoscape library and with this algorytm works
function tick() {
path.attr("d", function (d) {
var coordinatesP = findEdgeControlPoints(d);
return "M" + d.source.x + "," + d.source.y + "S" + coordinatesP.xp + "," + coordinatesP.yp + " " + d.target.x + "," + d.target.y;
});
hashTable = {};
nodes.attr("cx", function (d) { return d.x; })
.attr("cy", function (d) { return d.y; });
}
var findEdgeControlPoints = function (d) {
var midPointX = (d.source.x + d.target.x) / 2;
var midPointY = (d.source.y + d.target.y) / 2;
var displacementX, displacementY;
displacementX = d.target.y - d.source.y;
displacementY = d.source.x - d.target.x;
var displacementLength = Math.sqrt(displacementX * displacementX + displacementY * displacementY);
displacementX /= displacementLength;
displacementY /= displacementLength;
var distanceFromMidpoint = findPathDeltaControlPoint(d);
var xp = midPointX + displacementX * distanceFromMidpoint;
var yp = midPointY + displacementY * distanceFromMidpoint;
return {xp : xp, yp : yp};
};
var findPathDeltaControlPoint = function (edge) {
/*caso statico il primo al centro e tutti gli altri ai lati*/
/*conto le occorrenze */
var pairId,
delta,
TICK = 20;
pairId = edge.source.id > edge.target.id ?
edge.target.id + '-' + edge.source.id :
edge.source.id + '-' + edge.target.id;
if (hashTable[pairId] == undefined) {
hashTable[pairId] = [];
}
if (edge[pairId] == undefined) {
edge[pairId] = [];
}
if (edge[pairId].length == 0) {
edge[pairId].push(pairId);
}
hashTable[pairId].push(edge);
// Ceck if is the first occurence
var pairIdOccurence = hashTable[pairId].length;
if (pairIdOccurence == 1) {
delta = 0;
} else if (pairIdOccurence > 1) {
// Check if is equal
if (pairIdOccurence % 2 == 0) {
delta = (TICK * pairIdOccurence) / 2;
} else {
delta = -((TICK * (pairIdOccurence - 1)) / 2);
}
}
return delta;
};
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