将BigDecimal乘以100哪种方法更好? [英] Which method will be better when multiply 100 with BigDecimal?
问题描述
在这里,当我使用Java BigDecimal时遇到一个问题. 当我想将100乘以BigDecimal的对象时,哪种方法会更好.
Here I have a question when using Java BigDecimal. Which way will be better when I want to multiply 100 for a object of BigDecimal.
- 乘以10两次;
- movePointRight(2);
- scaleByPowerOfTen(2);
- 还有其他方法吗?请告诉我是否有.
顺便说一句,它将用于商业计算,因此我考虑的是精度而不是速度.
BTW, it will be used for commercial calculation, so I'm considering the precision rather than the speed.
推荐答案
选项3最快.选项1和2大致相同(选项一乘以十两次).相反,乘以100会接近选项3的速度.
Option 3 is the fastest. Options 1 and 2 are roughly the same (option one being to multiply by ten twice). Multiplying by 100 instead gets up near the speed of option 3.
这是我的测试代码:
import java.math.BigDecimal;
public class TestingStuff {
public static void main(String[] args){
BigDecimal d2 = new BigDecimal(0); // to load the big decimal class outside the loop
long start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++) {
BigDecimal d = new BigDecimal(99);
d2 = d.movePointRight(2);
}
long end = System.currentTimeMillis();
System.out.println("movePointRight: " + (end - start));
BigDecimal ten = new BigDecimal(10);
start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++) {
BigDecimal d = new BigDecimal(99);
d2 = d.multiply(ten).multiply(ten);
}
end = System.currentTimeMillis();
System.out.println("multiply: " + (end - start));
start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++) {
BigDecimal d = new BigDecimal(99);
d2 = d.scaleByPowerOfTen(2);
}
end = System.currentTimeMillis();
System.out.println("scaleByPowerOfTen: " + (end - start));
}
}
当然,您可以自己在自己的代码中尝试各种选项.如果您无法衡量差异,那么为什么要进行优化?
Of course you could just try the various options yourself in your own code. If you can't measure the difference, then why are you optimizing?
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