如何创建一个非常大的BigInteger [英] How to create a very large BigInteger

问题描述

我需要添加两个非常大的整数

  46376937677490009712648124896970078050417018260538
+ 37107287533902102798797998220837590246510135740250;

这是怎么了?

BigInteger f = 37107287533902102798797998220837590246510135740250;

如何使用BigInteger在Java中解决此问题?

解决方案

此处的问题是3710...将被解释为int，因此将超出范围.本质上，您要执行的操作是创建一个int，然后将其转换为BigInteger，而第一步将失败，因为int不能存储那么大的数字.

您需要使用采用String的构造函数:

BigInteger f = new BigInteger("37107287533902102798797998220837590246510135740250");

，当然也适用于您的其他BigInteger.

I need to add two very big integers

  46376937677490009712648124896970078050417018260538
+ 37107287533902102798797998220837590246510135740250;

What's wrong with this?

BigInteger f = 37107287533902102798797998220837590246510135740250;

How I can solve this problem in Java using BigInteger?

解决方案

The problem here is that 3710... will be interpreted as an int, and so it will be out of range. Essentially what you're trying to do is to create an int, and then convert it to a BigInteger, and the first step of this will fail because an int can't store a number that large.

You need to use the constructor that takes a String:

BigInteger f = new BigInteger("37107287533902102798797998220837590246510135740250");

and similarly for your other BigInteger, of course.

这篇关于如何创建一个非常大的BigInteger的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！